Solve (x-ac)/2=4

$$\frac { ( x - a c ) } { 2 } = 4$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{x-8}{c}\text{, }&c\neq 0\\a\in \mathrm{C}\text{, }&x=8\text{ and }c=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides by 2.

$$x-ac=4\times 2$$

Multiply 4 and 2 to get 8.

$$x-ac=8$$

Subtract x from both sides.

$$-ac=8-x$$

The equation is in standard form.

$$\left(-c\right)a=8-x$$

Divide both sides by -c.

$$\frac{\left(-c\right)a}{-c}=\frac{8-x}{-c}$$

Dividing by -c undoes the multiplication by -c.

$$a=\frac{8-x}{-c}$$

Divide -x+8 by -c.

$$a=\frac{x-8}{c}$$

Solve for c (complex solution)

$$\left\{\begin{matrix}c=\frac{x-8}{a}\text{, }&a\neq 0\\c\in \mathrm{C}\text{, }&x=8\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides by 2.

$$x-ac=4\times 2$$

Multiply 4 and 2 to get 8.

$$x-ac=8$$

Subtract x from both sides.

$$-ac=8-x$$

The equation is in standard form.

$$\left(-a\right)c=8-x$$

Divide both sides by -a.

$$\frac{\left(-a\right)c}{-a}=\frac{8-x}{-a}$$

Dividing by -a undoes the multiplication by -a.

$$c=\frac{8-x}{-a}$$

Divide -x+8 by -a.

$$c=\frac{x-8}{a}$$

Solve for a

$$\left\{\begin{matrix}a=\frac{x-8}{c}\text{, }&c\neq 0\\a\in \mathrm{R}\text{, }&x=8\text{ and }c=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides by 2.

$$x-ac=4\times 2$$

Multiply 4 and 2 to get 8.

$$x-ac=8$$

Subtract x from both sides.

$$-ac=8-x$$

The equation is in standard form.

$$\left(-c\right)a=8-x$$

Divide both sides by -c.

$$\frac{\left(-c\right)a}{-c}=\frac{8-x}{-c}$$

Dividing by -c undoes the multiplication by -c.

$$a=\frac{8-x}{-c}$$

Divide 8-x by -c.

$$a=\frac{x-8}{c}$$

Solve for c

$$\left\{\begin{matrix}c=\frac{x-8}{a}\text{, }&a\neq 0\\c\in \mathrm{R}\text{, }&x=8\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides by 2.

$$x-ac=4\times 2$$

Multiply 4 and 2 to get 8.

$$x-ac=8$$

Subtract x from both sides.

$$-ac=8-x$$

The equation is in standard form.

$$\left(-a\right)c=8-x$$

Divide both sides by -a.

$$\frac{\left(-a\right)c}{-a}=\frac{8-x}{-a}$$

Dividing by -a undoes the multiplication by -a.

$$c=\frac{8-x}{-a}$$

Divide 8-x by -a.

$$c=\frac{x-8}{a}$$