Solve (x-8)(x-1)(x-2)/(3-0)(3-1)(3-2)

$$\frac { ( x - 8 ) ( x - 1 ) ( x - 2 ) } { ( 3 - 0 ) ( 3 - 1 ) ( 3 - 2 ) }$$

Evaluate

$$\frac{\left(x-8\right)\left(x-2\right)\left(x-1\right)}{6}$$

Solution Steps

Subtract 0 from 3 to get 3.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{3\left(3-1\right)\left(3-2\right)}$$

Subtract 1 from 3 to get 2.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{3\times 2\left(3-2\right)}$$

Multiply 3 and 2 to get 6.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{6\left(3-2\right)}$$

Subtract 2 from 3 to get 1.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{6\times 1}$$

Multiply 6 and 1 to get 6.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{6}$$

Apply the distributive property by multiplying each term of x-8 by each term of x-1.

$$\frac{\left(x^{2}-x-8x+8\right)\left(x-2\right)}{6}$$

Combine -x and -8x to get -9x.

$$\frac{\left(x^{2}-9x+8\right)\left(x-2\right)}{6}$$

Apply the distributive property by multiplying each term of x^{2}-9x+8 by each term of x-2.

$$\frac{x^{3}-2x^{2}-9x^{2}+18x+8x-16}{6}$$

Combine -2x^{2} and -9x^{2} to get -11x^{2}.

$$\frac{x^{3}-11x^{2}+18x+8x-16}{6}$$

Combine 18x and 8x to get 26x.

$$\frac{x^{3}-11x^{2}+26x-16}{6}$$

Expand

$$\frac{x^{3}}{6}-\frac{11x^{2}}{6}+\frac{13x}{3}-\frac{8}{3}$$

Solution Steps

Subtract 0 from 3 to get 3.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{3\left(3-1\right)\left(3-2\right)}$$

Subtract 1 from 3 to get 2.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{3\times 2\left(3-2\right)}$$

Multiply 3 and 2 to get 6.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{6\left(3-2\right)}$$

Subtract 2 from 3 to get 1.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{6\times 1}$$

Multiply 6 and 1 to get 6.

$$\frac{\left(x-8\right)\left(x-1\right)\left(x-2\right)}{6}$$

Apply the distributive property by multiplying each term of x-8 by each term of x-1.

$$\frac{\left(x^{2}-x-8x+8\right)\left(x-2\right)}{6}$$

Combine -x and -8x to get -9x.

$$\frac{\left(x^{2}-9x+8\right)\left(x-2\right)}{6}$$

Apply the distributive property by multiplying each term of x^{2}-9x+8 by each term of x-2.

$$\frac{x^{3}-2x^{2}-9x^{2}+18x+8x-16}{6}$$

Combine -2x^{2} and -9x^{2} to get -11x^{2}.

$$\frac{x^{3}-11x^{2}+18x+8x-16}{6}$$

Combine 18x and 8x to get 26x.

$$\frac{x^{3}-11x^{2}+26x-16}{6}$$