Solve (e^2-a)*4-(e^2-a)*4/2^4>0

$$\frac { ( e ^ { 2 } - a ) \times 4 - ( e ^ { 2 } - a ) \times 4 } { 2 ^ { 4 } } > 0$$

Evaluate

Solution Steps

Combine \left(e^{2}-a\right)\times 4 and -\left(e^{2}-a\right)\times 4 to get 0.

$$\frac{0}{2^{4}}>0$$

Calculate 2 to the power of 4 and get 16.

$$\frac{0}{16}>0$$

Zero divided by any non-zero number gives zero.

$$0>0$$

Compare 0 and 0.

$$\text{false}$$