Solve (8-4)(3-15)-6(-8+7)^2/7-9

$$\frac { ( 8 - 4 ) ( 3 - 15 ) - 6 ( - 8 + 7 ) ^ { 2 } } { 7 - 9 }$$

Evaluate

$$27$$

Solution Steps

Subtract 4 from 8 to get 4.

$$\frac{4\left(3-15\right)-6\left(-8+7\right)^{2}}{7-9}$$

Subtract 15 from 3 to get -12.

$$\frac{4\left(-12\right)-6\left(-8+7\right)^{2}}{7-9}$$

Multiply 4 and -12 to get -48.

$$\frac{-48-6\left(-8+7\right)^{2}}{7-9}$$

Add -8 and 7 to get -1.

$$\frac{-48-6\left(-1\right)^{2}}{7-9}$$

Calculate -1 to the power of 2 and get 1.

$$\frac{-48-6\times 1}{7-9}$$

Multiply 6 and 1 to get 6.

$$\frac{-48-6}{7-9}$$

Subtract 6 from -48 to get -54.

$$\frac{-54}{7-9}$$

Subtract 9 from 7 to get -2.

$$\frac{-54}{-2}$$

Divide -54 by -2 to get 27.

$$27$$

Factor

$$3^{3}$$