Solve (79+11):97+(-15-40)/(63-86

$$\frac { ( 79 + 11 ) : 97 + ( - 15 - 40 ) } { ( 63 - 86 }$$

Evaluate

$$\frac{5245}{2231}\approx 2.350963693$$

Solution Steps

Add 79 and 11 to get 90.

$$\frac{\frac{90}{97}-15-40}{63-86}$$

Convert 15 to fraction \frac{1455}{97}.

$$\frac{\frac{90}{97}-\frac{1455}{97}-40}{63-86}$$

Since \frac{90}{97} and \frac{1455}{97} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{90-1455}{97}-40}{63-86}$$

Subtract 1455 from 90 to get -1365.

$$\frac{-\frac{1365}{97}-40}{63-86}$$

Convert 40 to fraction \frac{3880}{97}.

$$\frac{-\frac{1365}{97}-\frac{3880}{97}}{63-86}$$

Since -\frac{1365}{97} and \frac{3880}{97} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{-1365-3880}{97}}{63-86}$$

Subtract 3880 from -1365 to get -5245.

$$\frac{-\frac{5245}{97}}{63-86}$$

Subtract 86 from 63 to get -23.

$$\frac{-\frac{5245}{97}}{-23}$$

Express \frac{-\frac{5245}{97}}{-23} as a single fraction.

$$\frac{-5245}{97\left(-23\right)}$$

Multiply 97 and -23 to get -2231.

$$\frac{-5245}{-2231}$$

Fraction \frac{-5245}{-2231} can be simplified to \frac{5245}{2231} by removing the negative sign from both the numerator and the denominator.

$$\frac{5245}{2231}$$

Factor

$$\frac{5 \cdot 1049}{23 \cdot 97} = 2\frac{783}{2231} = 2.3509636934110265$$