Solve (53)^4+4*(49)^4/(53)^2+2(49)^2+5194=?

$$\frac { ( 53 ) ^ { 4 } + 4 * ( 49 ) ^ { 4 } } { ( 53 ) ^ { 2 } + 2 ( 49 ) ^ { 2 } + 5194 } = ?$$

Evaluate

$$2417$$

Solution Steps

Calculate 53 to the power of 4 and get 7890481.

$$\frac{7890481+4\times 49^{4}}{53^{2}+2\times 49^{2}+5194}$$

Calculate 49 to the power of 4 and get 5764801.

$$\frac{7890481+4\times 5764801}{53^{2}+2\times 49^{2}+5194}$$

Multiply 4 and 5764801 to get 23059204.

$$\frac{7890481+23059204}{53^{2}+2\times 49^{2}+5194}$$

Add 7890481 and 23059204 to get 30949685.

$$\frac{30949685}{53^{2}+2\times 49^{2}+5194}$$

Calculate 53 to the power of 2 and get 2809.

$$\frac{30949685}{2809+2\times 49^{2}+5194}$$

Calculate 49 to the power of 2 and get 2401.

$$\frac{30949685}{2809+2\times 2401+5194}$$

Multiply 2 and 2401 to get 4802.

$$\frac{30949685}{2809+4802+5194}$$

Add 2809 and 4802 to get 7611.

$$\frac{30949685}{7611+5194}$$

Add 7611 and 5194 to get 12805.

$$\frac{30949685}{12805}$$

Divide 30949685 by 12805 to get 2417.

$$2417$$

Factor

$$2417$$