Solve (53)^0+(-98)^0-(-13)^0/4divfrac{1{4}}

$$\frac { ( 53 ) ^ { 0 } + ( - 98 ) ^ { 0 } - ( - 13 ) ^ { 0 } } { 4 \div \frac { 1 } { 4 } }$$

Evaluate

$$\frac{1}{16}=0.0625$$

Solution Steps

Calculate 53 to the power of 0 and get 1.

$$\frac{1+\left(-98\right)^{0}-\left(-13\right)^{0}}{\frac{4}{\frac{1}{4}}}$$

Calculate -98 to the power of 0 and get 1.

$$\frac{1+1-\left(-13\right)^{0}}{\frac{4}{\frac{1}{4}}}$$

Add 1 and 1 to get 2.

$$\frac{2-\left(-13\right)^{0}}{\frac{4}{\frac{1}{4}}}$$

Calculate -13 to the power of 0 and get 1.

$$\frac{2-1}{\frac{4}{\frac{1}{4}}}$$

Subtract 1 from 2 to get 1.

$$\frac{1}{\frac{4}{\frac{1}{4}}}$$

Divide 4 by \frac{1}{4} by multiplying 4 by the reciprocal of \frac{1}{4}.

$$\frac{1}{4\times 4}$$

Multiply 4 and 4 to get 16.

$$\frac{1}{16}$$

Factor

$$\frac{1}{2 ^ {4}} = 0.0625$$