Solve (45-x)-23*25/3x=y

$$\frac { ( 45 - x ) - 23 \cdot 25 } { 3 x } = y$$

Solve for x

$$x=-\frac{530}{3y+1}$$

$$y\neq -\frac{1}{3}$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 3x.

$$45-x-23\times 25=y\times 3x$$

Multiply 23 and 25 to get 575.

$$45-x-575=y\times 3x$$

Subtract 575 from 45 to get -530.

$$-530-x=y\times 3x$$

Subtract y\times 3x from both sides.

$$-530-x-y\times 3x=0$$

Multiply -1 and 3 to get -3.

$$-530-x-3yx=0$$

Add 530 to both sides. Anything plus zero gives itself.

$$-x-3yx=530$$

Combine all terms containing x.

$$\left(-1-3y\right)x=530$$

The equation is in standard form.

$$\left(-3y-1\right)x=530$$

Divide both sides by -1-3y.

$$\frac{\left(-3y-1\right)x}{-3y-1}=\frac{530}{-3y-1}$$

Dividing by -1-3y undoes the multiplication by -1-3y.

$$x=\frac{530}{-3y-1}$$

Divide 530 by -1-3y.

$$x=-\frac{530}{3y+1}$$

Variable x cannot be equal to 0.

$$x=-\frac{530}{3y+1}\text{, }x\neq 0$$

Solve for y

$$y=-\frac{1}{3}-\frac{530}{3x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3x.

$$45-x-23\times 25=y\times 3x$$

Multiply 23 and 25 to get 575.

$$45-x-575=y\times 3x$$

Subtract 575 from 45 to get -530.

$$-530-x=y\times 3x$$

Swap sides so that all variable terms are on the left hand side.

$$y\times 3x=-530-x$$

The equation is in standard form.

$$3xy=-x-530$$

Divide both sides by 3x.

$$\frac{3xy}{3x}=\frac{-x-530}{3x}$$

Dividing by 3x undoes the multiplication by 3x.

$$y=\frac{-x-530}{3x}$$

Divide -530-x by 3x.

$$y=-\frac{1}{3}-\frac{530}{3x}$$