Solve (4m^2)^2-2m^3*2m/3m^4

$$\frac { ( 4 m ^ { 2 } ) ^ { 2 } - 2 m ^ { 3 } \times 2 m } { 3 m ^ { 4 } }$$

Evaluate

$$4$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$\frac{\left(4m^{2}\right)^{2}-2m^{4}\times 2}{3m^{4}}$$

Expand \left(4m^{2}\right)^{2}.

$$\frac{4^{2}\left(m^{2}\right)^{2}-2m^{4}\times 2}{3m^{4}}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$\frac{4^{2}m^{4}-2m^{4}\times 2}{3m^{4}}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{16m^{4}-2m^{4}\times 2}{3m^{4}}$$

Multiply 2 and 2 to get 4.

$$\frac{16m^{4}-4m^{4}}{3m^{4}}$$

Combine 16m^{4} and -4m^{4} to get 12m^{4}.

$$\frac{12m^{4}}{3m^{4}}$$

Cancel out 3m^{4} in both numerator and denominator.

$$4$$

Factor

$$2^{2}$$