Solve (4^2)^8-4/4^-7=

$$\frac { ( 4 ^ { 2 } ) ^ { 8 } - 4 } { 4 ^ { - 7 } } =$$

Evaluate

$$70368744112128$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 8 to get 16.

$$\frac{4^{16}-4}{4^{-7}}$$

Calculate 4 to the power of 16 and get 4294967296.

$$\frac{4294967296-4}{4^{-7}}$$

Subtract 4 from 4294967296 to get 4294967292.

$$\frac{4294967292}{4^{-7}}$$

Calculate 4 to the power of -7 and get \frac{1}{16384}.

$$\frac{4294967292}{\frac{1}{16384}}$$

Divide 4294967292 by \frac{1}{16384} by multiplying 4294967292 by the reciprocal of \frac{1}{16384}.

$$4294967292\times 16384$$

Multiply 4294967292 and 16384 to get 70368744112128.

$$70368744112128$$

Factor

$$2^{16}\times 3^{2}\times 7\times 11\times 31\times 151\times 331$$