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\frac{\left(4+\sqrt{3}\right)\left(2\sqrt{3}+2\right)}{8}
Subtract 4 from 12 to get 8.
\frac{8\sqrt{3}+8+2\left(\sqrt{3}\right)^{2}+2\sqrt{3}}{8}
Apply the distributive property by multiplying each term of 4+\sqrt{3} by each term of 2\sqrt{3}+2.
\frac{8\sqrt{3}+8+2\times 3+2\sqrt{3}}{8}
The square of \sqrt{3} is 3.
\frac{8\sqrt{3}+8+6+2\sqrt{3}}{8}
Multiply 2 and 3 to get 6.
\frac{8\sqrt{3}+14+2\sqrt{3}}{8}
Add 8 and 6 to get 14.
\frac{10\sqrt{3}+14}{8}
Combine 8\sqrt{3} and 2\sqrt{3} to get 10\sqrt{3}.