Solve (361)^3+(139)^3/(361)^2-361*139+(139)^2

$$\frac { ( 361 ) ^ { 3 } + ( 139 ) ^ { 3 } } { ( 361 ) ^ { 2 } - 361 \times 139 + ( 139 ) ^ { 2 } }$$

Evaluate

$$500$$

Solution Steps

Calculate 361 to the power of 3 and get 47045881.

$$\frac{47045881+139^{3}}{361^{2}-361\times 139+139^{2}}$$

Calculate 139 to the power of 3 and get 2685619.

$$\frac{47045881+2685619}{361^{2}-361\times 139+139^{2}}$$

Add 47045881 and 2685619 to get 49731500.

$$\frac{49731500}{361^{2}-361\times 139+139^{2}}$$

Calculate 361 to the power of 2 and get 130321.

$$\frac{49731500}{130321-361\times 139+139^{2}}$$

Multiply 361 and 139 to get 50179.

$$\frac{49731500}{130321-50179+139^{2}}$$

Subtract 50179 from 130321 to get 80142.

$$\frac{49731500}{80142+139^{2}}$$

Calculate 139 to the power of 2 and get 19321.

$$\frac{49731500}{80142+19321}$$

Add 80142 and 19321 to get 99463.

$$\frac{49731500}{99463}$$

Divide 49731500 by 99463 to get 500.

$$500$$

Factor

$$2^{2}\times 5^{3}$$