Solve (34^2+2100-3400)/34^2+2100

$$\frac { ( 34 ^ { 2 } + 2100 - 3400 ) } { 34 ^ { 2 } + 2100 }$$

Evaluate

$$-\frac{18}{407}\approx -0.044226044$$

Solution Steps

Calculate 34 to the power of 2 and get 1156.

$$\frac{1156+2100-3400}{34^{2}+2100}$$

Add 1156 and 2100 to get 3256.

$$\frac{3256-3400}{34^{2}+2100}$$

Subtract 3400 from 3256 to get -144.

$$\frac{-144}{34^{2}+2100}$$

Calculate 34 to the power of 2 and get 1156.

$$\frac{-144}{1156+2100}$$

Add 1156 and 2100 to get 3256.

$$\frac{-144}{3256}$$

Reduce the fraction \frac{-144}{3256} to lowest terms by extracting and canceling out 8.

$$-\frac{18}{407}$$

Factor

$$-\frac{18}{407} = -0.044226044226044224$$