Solve frac{(3^{2}-(5^2)+2^3*(8-16/2)/2^2)}{2^3}=

$$\frac { ( 3 ^ { 2 } - ( 5 ^ { 2 } ) + 2 ^ { 3 } \cdot \frac { ( 8 - \frac { 16 } { 2 } ) } { 2 ^ { 2 } } ) } { 2 ^ { 3 } } =$$

Evaluate

$$-2$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\frac{9-5^{2}+2^{3}\times \frac{8-\frac{16}{2}}{2^{2}}}{2^{3}}$$

Calculate 5 to the power of 2 and get 25.

$$\frac{9-25+2^{3}\times \frac{8-\frac{16}{2}}{2^{2}}}{2^{3}}$$

Subtract 25 from 9 to get -16.

$$\frac{-16+2^{3}\times \frac{8-\frac{16}{2}}{2^{2}}}{2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{-16+8\times \frac{8-\frac{16}{2}}{2^{2}}}{2^{3}}$$

Divide 16 by 2 to get 8.

$$\frac{-16+8\times \frac{8-8}{2^{2}}}{2^{3}}$$

Subtract 8 from 8 to get 0.

$$\frac{-16+8\times \frac{0}{2^{2}}}{2^{3}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{-16+8\times \frac{0}{4}}{2^{3}}$$

Zero divided by any non-zero number gives zero.

$$\frac{-16+8\times 0}{2^{3}}$$

Multiply 8 and 0 to get 0.

$$\frac{-16+0}{2^{3}}$$

Add -16 and 0 to get -16.

$$\frac{-16}{2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{-16}{8}$$

Divide -16 by 8 to get -2.

$$-2$$

Factor

$$-2$$