Solve (2x-1)(x+3)-2x^2+3/x-3=20

$$\frac { ( 2 x - 1 ) ( x + 3 ) - 2 x ^ { 2 } + 3 } { x - 3 } = 20$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

Variable x cannot be equal to 3 since division by zero is not defined. Multiply both sides of the equation by x-3.

$$\left(2x-1\right)\left(x+3\right)-2x^{2}+3=20\left(x-3\right)$$

Use the distributive property to multiply 2x-1 by x+3 and combine like terms.

$$2x^{2}+5x-3-2x^{2}+3=20\left(x-3\right)$$

Combine 2x^{2} and -2x^{2} to get 0.

$$5x-3+3=20\left(x-3\right)$$

Add -3 and 3 to get 0.

$$5x=20\left(x-3\right)$$

Use the distributive property to multiply 20 by x-3.

$$5x=20x-60$$

Subtract 20x from both sides.

$$5x-20x=-60$$

Combine 5x and -20x to get -15x.

$$-15x=-60$$

Divide both sides by -15.

$$x=\frac{-60}{-15}$$

Divide -60 by -15 to get 4.

$$x=4$$