Solve frac{(2^{2})^-2+(2^2)^-2}{2^-4}=

$$\frac { ( 2 ^ { 2 } ) ^ { - 2 } + ( 2 ^ { 2 } ) ^ { - 2 } } { 2 ^ { - 4 } } =$$

Evaluate

$$2$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and -2 to get -4.

$$\frac{2^{-4}+\left(2^{2}\right)^{-2}}{2^{-4}}$$

To raise a power to another power, multiply the exponents. Multiply 2 and -2 to get -4.

$$\frac{2^{-4}+2^{-4}}{2^{-4}}$$

Calculate 2 to the power of -4 and get \frac{1}{16}.

$$\frac{\frac{1}{16}+2^{-4}}{2^{-4}}$$

Calculate 2 to the power of -4 and get \frac{1}{16}.

$$\frac{\frac{1}{16}+\frac{1}{16}}{2^{-4}}$$

Add \frac{1}{16} and \frac{1}{16} to get \frac{1}{8}.

$$\frac{\frac{1}{8}}{2^{-4}}$$

Calculate 2 to the power of -4 and get \frac{1}{16}.

$$\frac{\frac{1}{8}}{\frac{1}{16}}$$

Divide \frac{1}{8} by \frac{1}{16} by multiplying \frac{1}{8} by the reciprocal of \frac{1}{16}.

$$\frac{1}{8}\times 16$$

Multiply \frac{1}{8} and 16 to get 2.

$$2$$

Factor

$$2$$