Solve (2+0-16-0*115)*3/(0*336+1*5-0*609)div0.4

$$\frac { ( 2 + 0 - 16 - 0 \cdot 115 ) \times 3 } { ( 0 \cdot 336 + 1 \cdot 5 - 0 \cdot 609 ) \div 0.4 }$$

Evaluate

$$-3.36$$

Solution Steps

Add 2 and 0 to get 2.

$$\frac{\left(2-16-0\times 115\right)\times 3}{\frac{0\times 336+1\times 5-0\times 609}{0.4}}$$

Subtract 16 from 2 to get -14.

$$\frac{\left(-14-0\times 115\right)\times 3}{\frac{0\times 336+1\times 5-0\times 609}{0.4}}$$

Multiply 0 and 115 to get 0.

$$\frac{\left(-14-0\right)\times 3}{\frac{0\times 336+1\times 5-0\times 609}{0.4}}$$

Subtract 0 from -14 to get -14.

$$\frac{-14\times 3}{\frac{0\times 336+1\times 5-0\times 609}{0.4}}$$

Multiply -14 and 3 to get -42.

$$\frac{-42}{\frac{0\times 336+1\times 5-0\times 609}{0.4}}$$

Multiply 0 and 336 to get 0. Multiply 1 and 5 to get 5.

$$\frac{-42}{\frac{0+5-0\times 609}{0.4}}$$

Add 0 and 5 to get 5.

$$\frac{-42}{\frac{5-0\times 609}{0.4}}$$

Multiply 0 and 609 to get 0.

$$\frac{-42}{\frac{5-0}{0.4}}$$

Subtract 0 from 5 to get 5.

$$\frac{-42}{\frac{5}{0.4}}$$

Expand \frac{5}{0.4} by multiplying both numerator and the denominator by 10.

$$\frac{-42}{\frac{50}{4}}$$

Reduce the fraction \frac{50}{4} to lowest terms by extracting and canceling out 2.

$$\frac{-42}{\frac{25}{2}}$$

Divide -42 by \frac{25}{2} by multiplying -42 by the reciprocal of \frac{25}{2}.

$$-42\times \frac{2}{25}$$

Express -42\times \frac{2}{25} as a single fraction.

$$\frac{-42\times 2}{25}$$

Multiply -42 and 2 to get -84.

$$\frac{-84}{25}$$

Fraction \frac{-84}{25} can be rewritten as -\frac{84}{25} by extracting the negative sign.

$$-\frac{84}{25}$$

Factor

$$-3.36$$