Solve (1-j3)(-2+j5)/1-j3t-2+35

$$\frac { ( 1 - j 3 ) ( - 2 + j 5 ) } { 1 - j 3 t - 2 + 35 }$$

Evaluate

$$\frac{\left(1-j_{3}\right)\left(j_{5}-2\right)}{34-j_{3}t}$$

Short Solution Steps

Subtract 2 from 1 to get -1.

$$\frac{\left(1-j_{3}\right)\left(-2+j_{5}\right)}{-1-j_{3}t+35}$$

Add -1 and 35 to get 34.

$$\frac{\left(1-j_{3}\right)\left(-2+j_{5}\right)}{34-j_{3}t}$$

Apply the distributive property by multiplying each term of 1-j_{3} by each term of -2+j_{5}.

$$\frac{-2+j_{5}+2j_{3}-j_{3}j_{5}}{34-j_{3}t}$$

Expand

$$\frac{-j_{3}j_{5}+j_{5}+2j_{3}-2}{34-j_{3}t}$$

Short Solution Steps

Subtract 2 from 1 to get -1.

$$\frac{\left(1-j_{3}\right)\left(-2+j_{5}\right)}{-1-j_{3}t+35}$$

Add -1 and 35 to get 34.

$$\frac{\left(1-j_{3}\right)\left(-2+j_{5}\right)}{34-j_{3}t}$$

Apply the distributive property by multiplying each term of 1-j_{3} by each term of -2+j_{5}.

$$\frac{-2+j_{5}+2j_{3}-j_{3}j_{5}}{34-j_{3}t}$$