Solve (1-3)^2+(3-3)^2+(5-3)^2/3

$$\frac { ( 1 - 3 ) ^ { 2 } + ( 3 - 3 ) ^ { 2 } + ( 5 - 3 ) ^ { 2 } } { 3 }$$

Evaluate

$$\frac{8}{3}\approx 2.666666667$$

Solution Steps

Subtract 3 from 1 to get -2.

$$\frac{\left(-2\right)^{2}+\left(3-3\right)^{2}+\left(5-3\right)^{2}}{3}$$

Calculate -2 to the power of 2 and get 4.

$$\frac{4+\left(3-3\right)^{2}+\left(5-3\right)^{2}}{3}$$

Subtract 3 from 3 to get 0.

$$\frac{4+0^{2}+\left(5-3\right)^{2}}{3}$$

Calculate 0 to the power of 2 and get 0.

$$\frac{4+0+\left(5-3\right)^{2}}{3}$$

Add 4 and 0 to get 4.

$$\frac{4+\left(5-3\right)^{2}}{3}$$

Subtract 3 from 5 to get 2.

$$\frac{4+2^{2}}{3}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{4+4}{3}$$

Add 4 and 4 to get 8.

$$\frac{8}{3}$$

Factor

$$\frac{2 ^ {3}}{3} = 2\frac{2}{3} = 2.6666666666666665$$