Solve (1-3/2)^2*(-2)^3/frac{-5+3{-2,3}}

$$\frac { ( 1 - \frac { 3 } { 2 } ) ^ { 2 } \cdot ( - 2 ) ^ { 3 } } { \frac { - 5 + 3 } { - 2,3 } }$$

Evaluate

$$-2,3$$

Solution Steps

Subtract \frac{3}{2} from 1 to get -\frac{1}{2}.

$$\frac{\left(-\frac{1}{2}\right)^{2}\left(-2\right)^{3}}{\frac{-5+3}{-2,3}}$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{\frac{1}{4}\left(-2\right)^{3}}{\frac{-5+3}{-2,3}}$$

Calculate -2 to the power of 3 and get -8.

$$\frac{\frac{1}{4}\left(-8\right)}{\frac{-5+3}{-2,3}}$$

Multiply \frac{1}{4} and -8 to get -2.

$$\frac{-2}{\frac{-5+3}{-2,3}}$$

Add -5 and 3 to get -2.

$$\frac{-2}{\frac{-2}{-2,3}}$$

Expand \frac{-2}{-2,3} by multiplying both numerator and the denominator by 10.

$$\frac{-2}{\frac{-20}{-23}}$$

Fraction \frac{-20}{-23} can be simplified to \frac{20}{23} by removing the negative sign from both the numerator and the denominator.

$$\frac{-2}{\frac{20}{23}}$$

Divide -2 by \frac{20}{23} by multiplying -2 by the reciprocal of \frac{20}{23}.

$$-2\times \frac{23}{20}$$

Multiply -2 and \frac{23}{20} to get -\frac{23}{10}.

$$-\frac{23}{10}$$

Factor

$$-2,3$$