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\frac{\left(1+\frac{15}{1000}\right)^{12}-1}{\frac{15}{100}}
Expand \frac{1.5}{100} by multiplying both numerator and the denominator by 10.
\frac{\left(1+\frac{3}{200}\right)^{12}-1}{\frac{15}{100}}
Reduce the fraction \frac{15}{1000} to lowest terms by extracting and canceling out 5.
\frac{\left(\frac{203}{200}\right)^{12}-1}{\frac{15}{100}}
Add 1 and \frac{3}{200} to get \frac{203}{200}.
\frac{\frac{4897252030306448390395044241}{4096000000000000000000000000}-1}{\frac{15}{100}}
Calculate \frac{203}{200} to the power of 12 and get \frac{4897252030306448390395044241}{4096000000000000000000000000}.
\frac{\frac{801252030306448390395044241}{4096000000000000000000000000}}{\frac{15}{100}}
Subtract 1 from \frac{4897252030306448390395044241}{4096000000000000000000000000} to get \frac{801252030306448390395044241}{4096000000000000000000000000}.
\frac{\frac{801252030306448390395044241}{4096000000000000000000000000}}{\frac{3}{20}}
Reduce the fraction \frac{15}{100} to lowest terms by extracting and canceling out 5.
\frac{801252030306448390395044241}{4096000000000000000000000000}\times \frac{20}{3}
Divide \frac{801252030306448390395044241}{4096000000000000000000000000} by \frac{3}{20} by multiplying \frac{801252030306448390395044241}{4096000000000000000000000000} by the reciprocal of \frac{3}{20}.
\frac{267084010102149463465014747}{204800000000000000000000000}
Multiply \frac{801252030306448390395044241}{4096000000000000000000000000} and \frac{20}{3} to get \frac{267084010102149463465014747}{204800000000000000000000000}.