Solve (-7)(-3)-(4)(3)/3[7div(3-10)]

$$\frac { ( - 7 ) ( - 3 ) - ( 4 ) ( 3 ) } { 3 [ 7 \div ( 3 - 10 ) ] }$$

Evaluate

$$-3$$

Solution Steps

Multiply -7 and -3 to get 21.

$$\frac{21-4\times 3}{3\times \frac{7}{3-10}}$$

Multiply 4 and 3 to get 12.

$$\frac{21-12}{3\times \frac{7}{3-10}}$$

Subtract 12 from 21 to get 9.

$$\frac{9}{3\times \frac{7}{3-10}}$$

Subtract 10 from 3 to get -7.

$$\frac{9}{3\times \frac{7}{-7}}$$

Divide 7 by -7 to get -1.

$$\frac{9}{3\left(-1\right)}$$

Multiply 3 and -1 to get -3.

$$\frac{9}{-3}$$

Divide 9 by -3 to get -3.

$$-3$$

Factor

$$-3$$