Solve frac{(-7)^{3}*7^{4}*(-49)^2}{7^4*(-7^3)^6}=

$$\frac { ( - 7 ) ^ { 3 } \times 7 ^ { 4 } \times ( - 49 ) ^ { 2 } } { 7 ^ { 4 } \times ( - 7 ^ { 3 } ) ^ { 6 } } =$$

Evaluate

$$-\frac{1}{1977326743}\approx -5.057333107 \cdot 10^{-10}$$

Solution Steps

Cancel out 7^{4} in both numerator and denominator.

$$\frac{\left(-49\right)^{2}\left(-7\right)^{3}}{\left(-7^{3}\right)^{6}}$$

Calculate -49 to the power of 2 and get 2401.

$$\frac{2401\left(-7\right)^{3}}{\left(-7^{3}\right)^{6}}$$

Calculate -7 to the power of 3 and get -343.

$$\frac{2401\left(-343\right)}{\left(-7^{3}\right)^{6}}$$

Multiply 2401 and -343 to get -823543.

$$\frac{-823543}{\left(-7^{3}\right)^{6}}$$

Calculate 7 to the power of 3 and get 343.

$$\frac{-823543}{\left(-343\right)^{6}}$$

Calculate -343 to the power of 6 and get 1628413597910449.

$$\frac{-823543}{1628413597910449}$$

Reduce the fraction \frac{-823543}{1628413597910449} to lowest terms by extracting and canceling out 823543.

$$-\frac{1}{1977326743}$$

Factor

$$-\frac{1}{1977326743} = -5.057333106630622 \times 10^{-10}$$