Solve (-5)^3*(-25)^2/(-125)^4*5^0

$$\frac { ( - 5 ) ^ { 3 } \cdot ( - 25 ) ^ { 2 } } { ( - 125 ) ^ { 4 } \cdot 5 ^ { 0 } }$$

Evaluate

$$-\frac{1}{3125}=-0.00032$$

Solution Steps

Calculate -5 to the power of 3 and get -125.

$$\frac{-125\left(-25\right)^{2}}{\left(-125\right)^{4}\times 5^{0}}$$

Calculate -25 to the power of 2 and get 625.

$$\frac{-125\times 625}{\left(-125\right)^{4}\times 5^{0}}$$

Multiply -125 and 625 to get -78125.

$$\frac{-78125}{\left(-125\right)^{4}\times 5^{0}}$$

Calculate -125 to the power of 4 and get 244140625.

$$\frac{-78125}{244140625\times 5^{0}}$$

Calculate 5 to the power of 0 and get 1.

$$\frac{-78125}{244140625\times 1}$$

Multiply 244140625 and 1 to get 244140625.

$$\frac{-78125}{244140625}$$

Reduce the fraction \frac{-78125}{244140625} to lowest terms by extracting and canceling out 78125.

$$-\frac{1}{3125}$$

Factor

$$-\frac{1}{3125} = -0.00032$$