Solve (-4)^3*72/2^2*3^3*(-8)^2

$$\frac { ( - 4 ) ^ { 3 } \cdot 72 } { 2 ^ { 2 } \cdot 3 ^ { 3 } \cdot ( - 8 ) ^ { 2 } }$$

Evaluate

$$-\frac{2}{3}\approx -0.666666667$$

Solution Steps

Calculate -4 to the power of 3 and get -64.

$$\frac{-64\times 72}{2^{2}\times 3^{3}\left(-8\right)^{2}}$$

Multiply -64 and 72 to get -4608.

$$\frac{-4608}{2^{2}\times 3^{3}\left(-8\right)^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{-4608}{4\times 3^{3}\left(-8\right)^{2}}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{-4608}{4\times 27\left(-8\right)^{2}}$$

Multiply 4 and 27 to get 108.

$$\frac{-4608}{108\left(-8\right)^{2}}$$

Calculate -8 to the power of 2 and get 64.

$$\frac{-4608}{108\times 64}$$

Multiply 108 and 64 to get 6912.

$$\frac{-4608}{6912}$$

Reduce the fraction \frac{-4608}{6912} to lowest terms by extracting and canceling out 2304.

$$-\frac{2}{3}$$

Factor

$$-\frac{2}{3} = -0.6666666666666666$$