Solve (-3x)^2/-3x^2

$$\frac { ( - 3 x ) ^ { 2 } } { - 3 x ^ { 2 } }$$

Evaluate

$$-3$$

Steps for the Product of Two Exponentials

Use the rules of exponents to simplify the expression.

$$\left(-3x^{1}\right)^{2}\times \frac{1}{-3x^{2}}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$\left(-3\right)^{2}\left(x^{1}\right)^{2}\times \frac{1}{-3}\times \frac{1}{x^{2}}$$

Use the Commutative Property of Multiplication.

$$\left(-3\right)^{2}\times \frac{1}{-3}\left(x^{1}\right)^{2}\times \frac{1}{x^{2}}$$

To raise a power to another power, multiply the exponents.

$$\left(-3\right)^{2}\times \frac{1}{-3}x^{2}x^{2\left(-1\right)}$$

Multiply 2 times -1.

$$\left(-3\right)^{2}\times \frac{1}{-3}x^{2}x^{-2}$$

To multiply powers of the same base, add their exponents.

$$\left(-3\right)^{2}\times \frac{1}{-3}x^{2-2}$$

Add the exponents 2 and -2.

$$\left(-3\right)^{2}\times \frac{1}{-3}x^{0}$$

To multiply powers of the same base, add their exponents.

$$\left(-3\right)^{2-1}x^{0}$$

Add the exponents 2 and -1.

$$\left(-3\right)^{1}x^{0}$$

For any term t, t^{1}=t.

$$-3x^{0}$$

For any term t except 0, t^{0}=1.

$$-3$$

Factor

$$-3$$