Solve (-1)^2020+2019^0/-3^2-(-2)^3

$$\frac { ( - 1 ) ^ { 2020 } + 2019 ^ { 0 } } { - 3 ^ { 2 } - ( - 2 ) ^ { 3 } }$$

Evaluate

$$-2$$

Solution Steps

Calculate -1 to the power of 2020 and get 1.

$$\frac{1+2019^{0}}{-3^{2}-\left(-2\right)^{3}}$$

Calculate 2019 to the power of 0 and get 1.

$$\frac{1+1}{-3^{2}-\left(-2\right)^{3}}$$

Add 1 and 1 to get 2.

$$\frac{2}{-3^{2}-\left(-2\right)^{3}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{2}{-9-\left(-2\right)^{3}}$$

Calculate -2 to the power of 3 and get -8.

$$\frac{2}{-9-\left(-8\right)}$$

The opposite of -8 is 8.

$$\frac{2}{-9+8}$$

Add -9 and 8 to get -1.

$$\frac{2}{-1}$$

Fraction \frac{2}{-1} can be rewritten as -2 by extracting the negative sign.

$$-2$$

Factor

$$-2$$