Solve frac{(sqrt{49}-sqrt{9})^3-sqrt{1}}{sqrt{25}+sqrt{16}}

$$\frac { ( \sqrt { 49 } - \sqrt { 9 } ) ^ { 3 } - \sqrt { 1 } } { \sqrt { 25 } + \sqrt { 16 } }$$

Evaluate

$$7$$

Solution Steps

Calculate the square root of 49 and get 7.

$$\frac{\left(7-\sqrt{9}\right)^{3}-\sqrt{1}}{\sqrt{25}+\sqrt{16}}$$

Calculate the square root of 9 and get 3.

$$\frac{\left(7-3\right)^{3}-\sqrt{1}}{\sqrt{25}+\sqrt{16}}$$

Subtract 3 from 7 to get 4.

$$\frac{4^{3}-\sqrt{1}}{\sqrt{25}+\sqrt{16}}$$

Calculate 4 to the power of 3 and get 64.

$$\frac{64-\sqrt{1}}{\sqrt{25}+\sqrt{16}}$$

Calculate the square root of 1 and get 1.

$$\frac{64-1}{\sqrt{25}+\sqrt{16}}$$

Subtract 1 from 64 to get 63.

$$\frac{63}{\sqrt{25}+\sqrt{16}}$$

Calculate the square root of 25 and get 5.

$$\frac{63}{5+\sqrt{16}}$$

Calculate the square root of 16 and get 4.

$$\frac{63}{5+4}$$

Add 5 and 4 to get 9.

$$\frac{63}{9}$$

Divide 63 by 9 to get 7.

$$7$$

Factor

$$7$$