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\frac{\left(\sqrt{3}\right)^{2}-\left(2\sqrt{3}\right)^{2}}{-3}
Consider \left(\sqrt{3}-2\sqrt{3}\right)\left(\sqrt{3}+2\sqrt{3}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{3-\left(2\sqrt{3}\right)^{2}}{-3}
The square of \sqrt{3} is 3.
\frac{3-2^{2}\left(\sqrt{3}\right)^{2}}{-3}
Expand \left(2\sqrt{3}\right)^{2}.
\frac{3-4\left(\sqrt{3}\right)^{2}}{-3}
Calculate 2 to the power of 2 and get 4.
\frac{3-4\times 3}{-3}
The square of \sqrt{3} is 3.
\frac{3-12}{-3}
Multiply 4 and 3 to get 12.
\frac{-9}{-3}
Subtract 12 from 3 to get -9.
3
Divide -9 by -3 to get 3.