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\frac{\left(\frac{24}{40}+\frac{5}{40}-\frac{7}{24}\right)\times \frac{3\times 13+1}{13}}{5-\frac{2}{3}}
Least common multiple of 5 and 8 is 40. Convert \frac{3}{5} and \frac{1}{8} to fractions with denominator 40.
\frac{\left(\frac{24+5}{40}-\frac{7}{24}\right)\times \frac{3\times 13+1}{13}}{5-\frac{2}{3}}
Since \frac{24}{40} and \frac{5}{40} have the same denominator, add them by adding their numerators.
\frac{\left(\frac{29}{40}-\frac{7}{24}\right)\times \frac{3\times 13+1}{13}}{5-\frac{2}{3}}
Add 24 and 5 to get 29.
\frac{\left(\frac{87}{120}-\frac{35}{120}\right)\times \frac{3\times 13+1}{13}}{5-\frac{2}{3}}
Least common multiple of 40 and 24 is 120. Convert \frac{29}{40} and \frac{7}{24} to fractions with denominator 120.
\frac{\frac{87-35}{120}\times \frac{3\times 13+1}{13}}{5-\frac{2}{3}}
Since \frac{87}{120} and \frac{35}{120} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{52}{120}\times \frac{3\times 13+1}{13}}{5-\frac{2}{3}}
Subtract 35 from 87 to get 52.
\frac{\frac{13}{30}\times \frac{3\times 13+1}{13}}{5-\frac{2}{3}}
Reduce the fraction \frac{52}{120} to lowest terms by extracting and canceling out 4.
\frac{\frac{13}{30}\times \frac{39+1}{13}}{5-\frac{2}{3}}
Multiply 3 and 13 to get 39.
\frac{\frac{13}{30}\times \frac{40}{13}}{5-\frac{2}{3}}
Add 39 and 1 to get 40.
\frac{\frac{13\times 40}{30\times 13}}{5-\frac{2}{3}}
Multiply \frac{13}{30} times \frac{40}{13} by multiplying numerator times numerator and denominator times denominator.
\frac{\frac{40}{30}}{5-\frac{2}{3}}
Cancel out 13 in both numerator and denominator.
\frac{\frac{4}{3}}{5-\frac{2}{3}}
Reduce the fraction \frac{40}{30} to lowest terms by extracting and canceling out 10.
\frac{\frac{4}{3}}{\frac{15}{3}-\frac{2}{3}}
Convert 5 to fraction \frac{15}{3}.
\frac{\frac{4}{3}}{\frac{15-2}{3}}
Since \frac{15}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{\frac{4}{3}}{\frac{13}{3}}
Subtract 2 from 15 to get 13.
\frac{4}{3}\times \frac{3}{13}
Divide \frac{4}{3} by \frac{13}{3} by multiplying \frac{4}{3} by the reciprocal of \frac{13}{3}.
\frac{4\times 3}{3\times 13}
Multiply \frac{4}{3} times \frac{3}{13} by multiplying numerator times numerator and denominator times denominator.
\frac{4}{13}
Cancel out 3 in both numerator and denominator.