Solve (3/2-1/3)^2-12^-1/5+3^-2=

$$\frac { ( \frac { 3 } { 2 } - \frac { 1 } { 3 } ) ^ { 2 } - 12 ^ { - 1 } } { 5 + 3 ^ { - 2 } } =$$

Evaluate

$$\frac{1}{4}=0.25$$

Solution Steps

Subtract \frac{1}{3} from \frac{3}{2} to get \frac{7}{6}.

$$\frac{\left(\frac{7}{6}\right)^{2}-12^{-1}}{5+3^{-2}}$$

Calculate \frac{7}{6} to the power of 2 and get \frac{49}{36}.

$$\frac{\frac{49}{36}-12^{-1}}{5+3^{-2}}$$

Calculate 12 to the power of -1 and get \frac{1}{12}.

$$\frac{\frac{49}{36}-\frac{1}{12}}{5+3^{-2}}$$

Subtract \frac{1}{12} from \frac{49}{36} to get \frac{23}{18}.

$$\frac{\frac{23}{18}}{5+3^{-2}}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$\frac{\frac{23}{18}}{5+\frac{1}{9}}$$

Add 5 and \frac{1}{9} to get \frac{46}{9}.

$$\frac{\frac{23}{18}}{\frac{46}{9}}$$

Divide \frac{23}{18} by \frac{46}{9} by multiplying \frac{23}{18} by the reciprocal of \frac{46}{9}.

$$\frac{23}{18}\times \frac{9}{46}$$

Multiply \frac{23}{18} and \frac{9}{46} to get \frac{1}{4}.

$$\frac{1}{4}$$

Factor

$$\frac{1}{2 ^ {2}} = 0.25$$