Solve (2/3)^8/(frac{3{5})^-3}=

$$\frac { ( \frac { 2 } { 3 } ) ^ { 8 } } { ( \frac { 3 } { 5 } ) ^ { - 3 } } =$$

Evaluate

$$\frac{256}{30375}\approx 0.008427984$$

Solution Steps

Calculate \frac{2}{3} to the power of 8 and get \frac{256}{6561}.

$$\frac{\frac{256}{6561}}{\left(\frac{3}{5}\right)^{-3}}$$

Calculate \frac{3}{5} to the power of -3 and get \frac{125}{27}.

$$\frac{\frac{256}{6561}}{\frac{125}{27}}$$

Divide \frac{256}{6561} by \frac{125}{27} by multiplying \frac{256}{6561} by the reciprocal of \frac{125}{27}.

$$\frac{256}{6561}\times \frac{27}{125}$$

Multiply \frac{256}{6561} and \frac{27}{125} to get \frac{256}{30375}.

$$\frac{256}{30375}$$

Factor

$$\frac{2 ^ {8}}{3 ^ {5} \cdot 5 ^ {3}} = 0.00842798353909465$$