Solve tan30^circ+tan45^circ/1-tan30^circtan45^circ

$$\frac { \tan 30 ^ { \circ } + \tan 45 ^ { \circ } } { 1 - \tan 30 ^ { \circ } \tan 45 ^ { \circ } }$$

Evaluate

$$\sqrt{3}+2\approx 3.732050808$$

Short Solution Steps

Get the value of \tan(30) from trigonometric values table.

$$\frac{\frac{\sqrt{3}}{3}+\tan(45)}{1-\tan(30)\tan(45)}$$

Get the value of \tan(45) from trigonometric values table.

$$\frac{\frac{\sqrt{3}}{3}+1}{1-\tan(30)\tan(45)}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{3}{3}.

$$\frac{\frac{\sqrt{3}}{3}+\frac{3}{3}}{1-\tan(30)\tan(45)}$$

Since \frac{\sqrt{3}}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{\sqrt{3}+3}{3}}{1-\tan(30)\tan(45)}$$

Get the value of \tan(30) from trigonometric values table.

$$\frac{\frac{\sqrt{3}+3}{3}}{1-\frac{\sqrt{3}}{3}\tan(45)}$$

Get the value of \tan(45) from trigonometric values table.

$$\frac{\frac{\sqrt{3}+3}{3}}{1-\frac{\sqrt{3}}{3}\times 1}$$

Express \frac{\sqrt{3}}{3}\times 1 as a single fraction.

$$\frac{\frac{\sqrt{3}+3}{3}}{1-\frac{\sqrt{3}}{3}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{3}{3}.

$$\frac{\frac{\sqrt{3}+3}{3}}{\frac{3}{3}-\frac{\sqrt{3}}{3}}$$

Since \frac{3}{3} and \frac{\sqrt{3}}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{\sqrt{3}+3}{3}}{\frac{3-\sqrt{3}}{3}}$$

Divide \frac{\sqrt{3}+3}{3} by \frac{3-\sqrt{3}}{3} by multiplying \frac{\sqrt{3}+3}{3} by the reciprocal of \frac{3-\sqrt{3}}{3}.

$$\frac{\left(\sqrt{3}+3\right)\times 3}{3\left(3-\sqrt{3}\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{\sqrt{3}+3}{-\sqrt{3}+3}$$

Rationalize the denominator of \frac{\sqrt{3}+3}{-\sqrt{3}+3} by multiplying numerator and denominator by -\sqrt{3}-3.

$$\frac{\left(\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}{\left(-\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}$$

Consider \left(-\sqrt{3}+3\right)\left(-\sqrt{3}-3\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\left(\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}{\left(-\sqrt{3}\right)^{2}-3^{2}}$$

Expand \left(-\sqrt{3}\right)^{2}.

$$\frac{\left(\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}{\left(-1\right)^{2}\left(\sqrt{3}\right)^{2}-3^{2}}$$

Calculate -1 to the power of 2 and get 1.

$$\frac{\left(\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}{1\left(\sqrt{3}\right)^{2}-3^{2}}$$

The square of \sqrt{3} is 3.

$$\frac{\left(\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}{1\times 3-3^{2}}$$

Multiply 1 and 3 to get 3.

$$\frac{\left(\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}{3-3^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{\left(\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}{3-9}$$

Subtract 9 from 3 to get -6.

$$\frac{\left(\sqrt{3}+3\right)\left(-\sqrt{3}-3\right)}{-6}$$

Use the distributive property to multiply \sqrt{3}+3 by -\sqrt{3}-3 and combine like terms.

$$\frac{-\left(\sqrt{3}\right)^{2}-6\sqrt{3}-9}{-6}$$

The square of \sqrt{3} is 3.

$$\frac{-3-6\sqrt{3}-9}{-6}$$

Subtract 9 from -3 to get -12.

$$\frac{-12-6\sqrt{3}}{-6}$$

Divide each term of -12-6\sqrt{3} by -6 to get 2+\sqrt{3}.

$$2+\sqrt{3}$$