Solve frac{sqrt[3]{27^2}*sqrt[3]{27}}{sqrt[6]{729}}=

$$\frac { \sqrt[ 3 ] { 27 ^ { 2 } } \cdot \sqrt[ 3 ] { 27 } } { \sqrt[ 6 ] { 729 } } =$$

Evaluate

$$9$$

Solution Steps

Calculate 27 to the power of 2 and get 729.

$$\frac{\sqrt[3]{729}\sqrt[3]{27}}{\sqrt[6]{729}}$$

Calculate \sqrt[3]{729} and get 9.

$$\frac{9\sqrt[3]{27}}{\sqrt[6]{729}}$$

Calculate \sqrt[3]{27} and get 3.

$$\frac{9\times 3}{\sqrt[6]{729}}$$

Multiply 9 and 3 to get 27.

$$\frac{27}{\sqrt[6]{729}}$$

Calculate \sqrt[6]{729} and get 3.

$$\frac{27}{3}$$

Divide 27 by 3 to get 9.

$$9$$

Factor

$$3^{2}$$