Solve frac{sqrt{9}-2}{-10+2^3+(-2)^2}

$$\frac { \sqrt { 9 } - 2 } { - 10 + 2 ^ { 3 } + ( - 2 ) ^ { 2 } }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Calculate the square root of 9 and get 3.

$$\frac{3-2}{-10+2^{3}+\left(-2\right)^{2}}$$

Subtract 2 from 3 to get 1.

$$\frac{1}{-10+2^{3}+\left(-2\right)^{2}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{1}{-10+8+\left(-2\right)^{2}}$$

Add -10 and 8 to get -2.

$$\frac{1}{-2+\left(-2\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$\frac{1}{-2+4}$$

Add -2 and 4 to get 2.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$