Evaluate
\sqrt{3}+5\approx 6.732050808
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\frac{\sqrt{12}+10}{2}
Add 9 and 3 to get 12.
\frac{2\sqrt{3}+10}{2}
Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.
\sqrt{3}+5
Divide each term of 2\sqrt{3}+10 by 2 to get \sqrt{3}+5.
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