Solve frac{sqrt{6}-sqrt{2}}{2}+frac{sqrt{3}+1}{2}

$$\frac { \sqrt { 6 } - \sqrt { 2 } } { 2 } + \frac { \sqrt { 3 } + 1 } { 2 }$$

Evaluate

$$\frac{\sqrt{3}+\sqrt{6}+1-\sqrt{2}}{2}\approx 1.883663494$$

Short Solution Steps

Since \frac{\sqrt{6}-\sqrt{2}}{2} and \frac{\sqrt{3}+1}{2} have the same denominator, add them by adding their numerators.

$$\frac{\sqrt{6}-\sqrt{2}+\sqrt{3}+1}{2}$$

Factor

$$\frac{\sqrt{3} + \sqrt{6} + 1 - \sqrt{2}}{2} = 1.8836634939894803$$