Solve frac{sqrt{6}}{3}+x=1

$$\frac { \sqrt { 6 } } { 3 } + x = 1$$

Solve for x

$$x=-\frac{\sqrt{6}}{3}+1\approx 0.183503419$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$\sqrt{6}+3x=3$$

Subtract \sqrt{6} from both sides.

$$3x=3-\sqrt{6}$$

Divide both sides by 3.

$$\frac{3x}{3}=\frac{3-\sqrt{6}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=\frac{3-\sqrt{6}}{3}$$

Divide 3-\sqrt{6} by 3.

$$x=-\frac{\sqrt{6}}{3}+1$$