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\frac{\sqrt{6}+2\sqrt{2}}{\sqrt{23}}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{\left(\sqrt{6}+2\sqrt{2}\right)\sqrt{23}}{\left(\sqrt{23}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{6}+2\sqrt{2}}{\sqrt{23}} by multiplying numerator and denominator by \sqrt{23}.
\frac{\left(\sqrt{6}+2\sqrt{2}\right)\sqrt{23}}{23}
The square of \sqrt{23} is 23.
\frac{\sqrt{6}\sqrt{23}+2\sqrt{2}\sqrt{23}}{23}
Use the distributive property to multiply \sqrt{6}+2\sqrt{2} by \sqrt{23}.
\frac{\sqrt{138}+2\sqrt{2}\sqrt{23}}{23}
To multiply \sqrt{6} and \sqrt{23}, multiply the numbers under the square root.
\frac{\sqrt{138}+2\sqrt{46}}{23}
To multiply \sqrt{2} and \sqrt{23}, multiply the numbers under the square root.