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\left(\sqrt{6}+\sqrt{2}\right)x=40
Multiply both sides of the equation by 4.
\left(\sqrt{2}+\sqrt{6}\right)x=40
The equation is in standard form.
\frac{\left(\sqrt{2}+\sqrt{6}\right)x}{\sqrt{2}+\sqrt{6}}=\frac{40}{\sqrt{2}+\sqrt{6}}
Divide both sides by \sqrt{6}+\sqrt{2}.
x=\frac{40}{\sqrt{2}+\sqrt{6}}
Dividing by \sqrt{6}+\sqrt{2} undoes the multiplication by \sqrt{6}+\sqrt{2}.
x=10\sqrt{6}-10\sqrt{2}
Divide 40 by \sqrt{6}+\sqrt{2}.