Solve frac{sqrt{5}}{36}*6^2/3*5=

$$\frac { \sqrt { 5 } } { 36 } \times \frac { 6 ^ { 2 } } { 3 \cdot 5 } =$$

Evaluate

$$\frac{\sqrt{5}}{15}\approx 0.149071198$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\frac{\sqrt{5}}{36}\times \frac{36}{3\times 5}$$

Multiply 3 and 5 to get 15.

$$\frac{\sqrt{5}}{36}\times \frac{36}{15}$$

Reduce the fraction \frac{36}{15} to lowest terms by extracting and canceling out 3.

$$\frac{\sqrt{5}}{36}\times \frac{12}{5}$$

Multiply \frac{\sqrt{5}}{36} times \frac{12}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\sqrt{5}\times 12}{36\times 5}$$

Cancel out 12 in both numerator and denominator.

$$\frac{\sqrt{5}}{3\times 5}$$

Multiply 3 and 5 to get 15.

$$\frac{\sqrt{5}}{15}$$