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\frac{\sqrt{42}\sqrt{6}}{2\left(\sqrt{6}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{42}}{2\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
\frac{\sqrt{42}\sqrt{6}}{2\times 6}
The square of \sqrt{6} is 6.
\frac{\sqrt{6}\sqrt{7}\sqrt{6}}{2\times 6}
Factor 42=6\times 7. Rewrite the square root of the product \sqrt{6\times 7} as the product of square roots \sqrt{6}\sqrt{7}.
\frac{6\sqrt{7}}{2\times 6}
Multiply \sqrt{6} and \sqrt{6} to get 6.
\frac{6\sqrt{7}}{12}
Multiply 2 and 6 to get 12.
\frac{1}{2}\sqrt{7}
Divide 6\sqrt{7} by 12 to get \frac{1}{2}\sqrt{7}.