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\frac{2+\sqrt{2\times \frac{1}{2}}}{2}-\frac{\sqrt{3\times \frac{1}{3}}+\sqrt{8\times \frac{1}{2}}}{4}
Calculate the square root of 4 and get 2.
\frac{2+\sqrt{1}}{2}-\frac{\sqrt{3\times \frac{1}{3}}+\sqrt{8\times \frac{1}{2}}}{4}
Cancel out 2 and 2.
\frac{2+1}{2}-\frac{\sqrt{3\times \frac{1}{3}}+\sqrt{8\times \frac{1}{2}}}{4}
Calculate the square root of 1 and get 1.
\frac{3}{2}-\frac{\sqrt{3\times \frac{1}{3}}+\sqrt{8\times \frac{1}{2}}}{4}
Add 2 and 1 to get 3.
\frac{3}{2}-\frac{\sqrt{1}+\sqrt{8\times \frac{1}{2}}}{4}
Cancel out 3 and 3.
\frac{3}{2}-\frac{1+\sqrt{8\times \frac{1}{2}}}{4}
Calculate the square root of 1 and get 1.
\frac{3}{2}-\frac{1+\sqrt{\frac{8}{2}}}{4}
Multiply 8 and \frac{1}{2} to get \frac{8}{2}.
\frac{3}{2}-\frac{1+\sqrt{4}}{4}
Divide 8 by 2 to get 4.
\frac{3}{2}-\frac{1+2}{4}
Calculate the square root of 4 and get 2.
\frac{3}{2}-\frac{3}{4}
Add 1 and 2 to get 3.
\frac{6}{4}-\frac{3}{4}
Least common multiple of 2 and 4 is 4. Convert \frac{3}{2} and \frac{3}{4} to fractions with denominator 4.
\frac{6-3}{4}
Since \frac{6}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.
\frac{3}{4}
Subtract 3 from 6 to get 3.