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Differentiate w.r.t. x
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\frac{\sqrt{3}\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}x
Rationalize the denominator of \frac{\sqrt{3}}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\sqrt{3}\sqrt{3}}{2\times 3}x
The square of \sqrt{3} is 3.
\frac{3}{2\times 3}x
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{3}{6}x
Multiply 2 and 3 to get 6.
\frac{1}{2}x
Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.
\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\sqrt{3}\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}x)
Rationalize the denominator of \frac{\sqrt{3}}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\sqrt{3}\sqrt{3}}{2\times 3}x)
The square of \sqrt{3} is 3.
\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3}{2\times 3}x)
Multiply \sqrt{3} and \sqrt{3} to get 3.
\frac{\mathrm{d}}{\mathrm{d}x}(\frac{3}{6}x)
Multiply 2 and 3 to get 6.
\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{2}x)
Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.
\frac{1}{2}x^{1-1}
The derivative of ax^{n} is nax^{n-1}.
\frac{1}{2}x^{0}
Subtract 1 from 1.
\frac{1}{2}\times 1
For any term t except 0, t^{0}=1.
\frac{1}{2}
For any term t, t\times 1=t and 1t=t.