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\frac{2\sqrt{3}}{\sqrt{2}-1}
Combine \sqrt{3} and \sqrt{3} to get 2\sqrt{3}.
\frac{2\sqrt{3}\left(\sqrt{2}+1\right)}{\left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right)}
Rationalize the denominator of \frac{2\sqrt{3}}{\sqrt{2}-1} by multiplying numerator and denominator by \sqrt{2}+1.
\frac{2\sqrt{3}\left(\sqrt{2}+1\right)}{\left(\sqrt{2}\right)^{2}-1^{2}}
Consider \left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{2\sqrt{3}\left(\sqrt{2}+1\right)}{2-1}
Square \sqrt{2}. Square 1.
\frac{2\sqrt{3}\left(\sqrt{2}+1\right)}{1}
Subtract 1 from 2 to get 1.
2\sqrt{3}\left(\sqrt{2}+1\right)
Anything divided by one gives itself.
2\sqrt{3}\sqrt{2}+2\sqrt{3}
Use the distributive property to multiply 2\sqrt{3} by \sqrt{2}+1.
2\sqrt{6}+2\sqrt{3}
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.