Solve frac{sqrt{2-sqrt[3]{-8}}}{sqrt{16}}=

$$\frac { \sqrt { 2 - \sqrt[ 3 ] { - 8 } } } { \sqrt { 16 } } =$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Calculate \sqrt[3]{-8} and get -2.

$$\frac{\sqrt{2-\left(-2\right)}}{\sqrt{16}}$$

The opposite of -2 is 2.

$$\frac{\sqrt{2+2}}{\sqrt{16}}$$

Add 2 and 2 to get 4.

$$\frac{\sqrt{4}}{\sqrt{16}}$$

Calculate the square root of 4 and get 2.

$$\frac{2}{\sqrt{16}}$$

Calculate the square root of 16 and get 4.

$$\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$