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\frac{\left(\sqrt{2}-2\right)\left(\sqrt{2}+1\right)}{\left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right)}+\sqrt{8}-\sqrt{18}
Rationalize the denominator of \frac{\sqrt{2}-2}{\sqrt{2}-1} by multiplying numerator and denominator by \sqrt{2}+1.
\frac{\left(\sqrt{2}-2\right)\left(\sqrt{2}+1\right)}{\left(\sqrt{2}\right)^{2}-1^{2}}+\sqrt{8}-\sqrt{18}
Consider \left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(\sqrt{2}-2\right)\left(\sqrt{2}+1\right)}{2-1}+\sqrt{8}-\sqrt{18}
Square \sqrt{2}. Square 1.
\frac{\left(\sqrt{2}-2\right)\left(\sqrt{2}+1\right)}{1}+\sqrt{8}-\sqrt{18}
Subtract 1 from 2 to get 1.
\left(\sqrt{2}-2\right)\left(\sqrt{2}+1\right)+\sqrt{8}-\sqrt{18}
Anything divided by one gives itself.
\left(\sqrt{2}-2\right)\left(\sqrt{2}+1\right)+2\sqrt{2}-\sqrt{18}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\left(\sqrt{2}-2\right)\left(\sqrt{2}+1\right)+2\sqrt{2}-3\sqrt{2}
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
\left(\sqrt{2}-2\right)\left(\sqrt{2}+1\right)-\sqrt{2}
Combine 2\sqrt{2} and -3\sqrt{2} to get -\sqrt{2}.
\left(\sqrt{2}\right)^{2}+\sqrt{2}-2\sqrt{2}-2-\sqrt{2}
Apply the distributive property by multiplying each term of \sqrt{2}-2 by each term of \sqrt{2}+1.
2+\sqrt{2}-2\sqrt{2}-2-\sqrt{2}
The square of \sqrt{2} is 2.
2-\sqrt{2}-2-\sqrt{2}
Combine \sqrt{2} and -2\sqrt{2} to get -\sqrt{2}.
-\sqrt{2}-\sqrt{2}
Subtract 2 from 2 to get 0.
-2\sqrt{2}
Combine -\sqrt{2} and -\sqrt{2} to get -2\sqrt{2}.