Solve frac{sqrt{2}}{2sqrt{2}-sqrt{3}}

$$\frac { \sqrt { 2 } } { 2 \sqrt { 2 } - \sqrt { 3 } }$$

Evaluate

$$\frac{\sqrt{6}+4}{5}\approx 1.289897949$$

Solution Steps

Rationalize the denominator of \frac{\sqrt{2}}{2\sqrt{2}-\sqrt{3}} by multiplying numerator and denominator by 2\sqrt{2}+\sqrt{3}.

$$\frac{\sqrt{2}\left(2\sqrt{2}+\sqrt{3}\right)}{\left(2\sqrt{2}-\sqrt{3}\right)\left(2\sqrt{2}+\sqrt{3}\right)}$$

Consider \left(2\sqrt{2}-\sqrt{3}\right)\left(2\sqrt{2}+\sqrt{3}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\sqrt{2}\left(2\sqrt{2}+\sqrt{3}\right)}{\left(2\sqrt{2}\right)^{2}-\left(\sqrt{3}\right)^{2}}$$

Expand \left(2\sqrt{2}\right)^{2}.

$$\frac{\sqrt{2}\left(2\sqrt{2}+\sqrt{3}\right)}{2^{2}\left(\sqrt{2}\right)^{2}-\left(\sqrt{3}\right)^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{\sqrt{2}\left(2\sqrt{2}+\sqrt{3}\right)}{4\left(\sqrt{2}\right)^{2}-\left(\sqrt{3}\right)^{2}}$$

The square of \sqrt{2} is 2.

$$\frac{\sqrt{2}\left(2\sqrt{2}+\sqrt{3}\right)}{4\times 2-\left(\sqrt{3}\right)^{2}}$$

Multiply 4 and 2 to get 8.

$$\frac{\sqrt{2}\left(2\sqrt{2}+\sqrt{3}\right)}{8-\left(\sqrt{3}\right)^{2}}$$

The square of \sqrt{3} is 3.

$$\frac{\sqrt{2}\left(2\sqrt{2}+\sqrt{3}\right)}{8-3}$$

Subtract 3 from 8 to get 5.

$$\frac{\sqrt{2}\left(2\sqrt{2}+\sqrt{3}\right)}{5}$$

Use the distributive property to multiply \sqrt{2} by 2\sqrt{2}+\sqrt{3}.

$$\frac{2\left(\sqrt{2}\right)^{2}+\sqrt{2}\sqrt{3}}{5}$$

The square of \sqrt{2} is 2.

$$\frac{2\times 2+\sqrt{2}\sqrt{3}}{5}$$

Multiply 2 and 2 to get 4.

$$\frac{4+\sqrt{2}\sqrt{3}}{5}$$

To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.

$$\frac{4+\sqrt{6}}{5}$$