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\frac{\sqrt{17}-3\sqrt{2}}{\sqrt{2}\sqrt{5}}
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
\frac{\sqrt{17}-3\sqrt{2}}{\sqrt{10}}
To multiply \sqrt{2} and \sqrt{5}, multiply the numbers under the square root.
\frac{\left(\sqrt{17}-3\sqrt{2}\right)\sqrt{10}}{\left(\sqrt{10}\right)^{2}}
Rationalize the denominator of \frac{\sqrt{17}-3\sqrt{2}}{\sqrt{10}} by multiplying numerator and denominator by \sqrt{10}.
\frac{\left(\sqrt{17}-3\sqrt{2}\right)\sqrt{10}}{10}
The square of \sqrt{10} is 10.
\frac{\sqrt{17}\sqrt{10}-3\sqrt{2}\sqrt{10}}{10}
Use the distributive property to multiply \sqrt{17}-3\sqrt{2} by \sqrt{10}.
\frac{\sqrt{170}-3\sqrt{2}\sqrt{10}}{10}
To multiply \sqrt{17} and \sqrt{10}, multiply the numbers under the square root.
\frac{\sqrt{170}-3\sqrt{2}\sqrt{2}\sqrt{5}}{10}
Factor 10=2\times 5. Rewrite the square root of the product \sqrt{2\times 5} as the product of square roots \sqrt{2}\sqrt{5}.
\frac{\sqrt{170}-3\times 2\sqrt{5}}{10}
Multiply \sqrt{2} and \sqrt{2} to get 2.
\frac{\sqrt{170}-6\sqrt{5}}{10}
Multiply -3 and 2 to get -6.