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\frac{\sqrt{10}}{6}\times \frac{4\sqrt{3}\sqrt{2}}{\left(\sqrt{2}\right)^{2}}
Rationalize the denominator of \frac{4\sqrt{3}}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{\sqrt{10}}{6}\times \frac{4\sqrt{3}\sqrt{2}}{2}
The square of \sqrt{2} is 2.
\frac{\sqrt{10}}{6}\times \frac{4\sqrt{6}}{2}
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.
\frac{\sqrt{10}}{6}\times 2\sqrt{6}
Divide 4\sqrt{6} by 2 to get 2\sqrt{6}.
\frac{\sqrt{10}}{3}\sqrt{6}
Cancel out 6, the greatest common factor in 2 and 6.
\frac{\sqrt{10}\sqrt{6}}{3}
Express \frac{\sqrt{10}}{3}\sqrt{6} as a single fraction.
\frac{\sqrt{60}}{3}
To multiply \sqrt{10} and \sqrt{6}, multiply the numbers under the square root.
\frac{2\sqrt{15}}{3}
Factor 60=2^{2}\times 15. Rewrite the square root of the product \sqrt{2^{2}\times 15} as the product of square roots \sqrt{2^{2}}\sqrt{15}. Take the square root of 2^{2}.